Optimal. Leaf size=698 \[ -\frac{15 i d^2 2^{-n-7} e^{-\frac{2 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}-\frac{3 i d^2 2^{-2 n-7} e^{-\frac{4 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}-\frac{i d^2 2^{-n-7} 3^{-n-1} e^{-\frac{6 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{15 i d^2 2^{-n-7} e^{\frac{2 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{3 i d^2 2^{-2 n-7} e^{\frac{4 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{i d^2 2^{-n-7} 3^{-n-1} e^{\frac{6 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{5 d^2 \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{n+1}}{16 b c (n+1) \sqrt{1-c^2 x^2}} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.576922, antiderivative size = 698, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 5, integrand size = 26, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.192, Rules used = {4663, 4661, 3312, 3307, 2181} \[ -\frac{15 i d^2 2^{-n-7} e^{-\frac{2 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}-\frac{3 i d^2 2^{-2 n-7} e^{-\frac{4 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}-\frac{i d^2 2^{-n-7} 3^{-n-1} e^{-\frac{6 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{15 i d^2 2^{-n-7} e^{\frac{2 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{3 i d^2 2^{-2 n-7} e^{\frac{4 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{i d^2 2^{-n-7} 3^{-n-1} e^{\frac{6 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{5 d^2 \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{n+1}}{16 b c (n+1) \sqrt{1-c^2 x^2}} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 4663
Rule 4661
Rule 3312
Rule 3307
Rule 2181
Rubi steps
\begin{align*} \int \left (d-c^2 d x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )^n \, dx &=\frac{\left (d^2 \sqrt{d-c^2 d x^2}\right ) \int \left (1-c^2 x^2\right )^{5/2} \left (a+b \sin ^{-1}(c x)\right )^n \, dx}{\sqrt{1-c^2 x^2}}\\ &=\frac{\left (d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int (a+b x)^n \cos ^6(x) \, dx,x,\sin ^{-1}(c x)\right )}{c \sqrt{1-c^2 x^2}}\\ &=\frac{\left (d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int \left (\frac{5}{16} (a+b x)^n+\frac{15}{32} (a+b x)^n \cos (2 x)+\frac{3}{16} (a+b x)^n \cos (4 x)+\frac{1}{32} (a+b x)^n \cos (6 x)\right ) \, dx,x,\sin ^{-1}(c x)\right )}{c \sqrt{1-c^2 x^2}}\\ &=\frac{5 d^2 \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{1+n}}{16 b c (1+n) \sqrt{1-c^2 x^2}}+\frac{\left (d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int (a+b x)^n \cos (6 x) \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt{1-c^2 x^2}}+\frac{\left (3 d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int (a+b x)^n \cos (4 x) \, dx,x,\sin ^{-1}(c x)\right )}{16 c \sqrt{1-c^2 x^2}}+\frac{\left (15 d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int (a+b x)^n \cos (2 x) \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt{1-c^2 x^2}}\\ &=\frac{5 d^2 \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{1+n}}{16 b c (1+n) \sqrt{1-c^2 x^2}}+\frac{\left (d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int e^{-6 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt{1-c^2 x^2}}+\frac{\left (d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int e^{6 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt{1-c^2 x^2}}+\frac{\left (3 d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int e^{-4 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt{1-c^2 x^2}}+\frac{\left (3 d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int e^{4 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{32 c \sqrt{1-c^2 x^2}}+\frac{\left (15 d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int e^{-2 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt{1-c^2 x^2}}+\frac{\left (15 d^2 \sqrt{d-c^2 d x^2}\right ) \operatorname{Subst}\left (\int e^{2 i x} (a+b x)^n \, dx,x,\sin ^{-1}(c x)\right )}{64 c \sqrt{1-c^2 x^2}}\\ &=\frac{5 d^2 \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^{1+n}}{16 b c (1+n) \sqrt{1-c^2 x^2}}-\frac{15 i 2^{-7-n} d^2 e^{-\frac{2 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,-\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{15 i 2^{-7-n} d^2 e^{\frac{2 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}-\frac{3 i 2^{-7-2 n} d^2 e^{-\frac{4 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,-\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{3 i 2^{-7-2 n} d^2 e^{\frac{4 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}-\frac{i 2^{-7-n} 3^{-1-n} d^2 e^{-\frac{6 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,-\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}+\frac{i 2^{-7-n} 3^{-1-n} d^2 e^{\frac{6 i a}{b}} \sqrt{d-c^2 d x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \Gamma \left (1+n,\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )}{c \sqrt{1-c^2 x^2}}\\ \end{align*}
Mathematica [A] time = 4.33457, size = 477, normalized size = 0.68 \[ \frac{d^3 \sqrt{1-c^2 x^2} \left (a+b \sin ^{-1}(c x)\right )^n \left (9 i 4^{-n} e^{\frac{4 i a}{b}} \left (\frac{\left (a+b \sin ^{-1}(c x)\right )^2}{b^2}\right )^{-n} \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^n \text{Gamma}\left (n+1,\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )+i 6^{-n} e^{\frac{6 i a}{b}} \left (\frac{\left (a+b \sin ^{-1}(c x)\right )^2}{b^2}\right )^{-n} \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^n \text{Gamma}\left (n+1,\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )-9 i 4^{-n} e^{-\frac{4 i a}{b}} \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^n \left (\frac{\left (a+b \sin ^{-1}(c x)\right )^2}{b^2}\right )^{-n} \text{Gamma}\left (n+1,-\frac{4 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )-i 6^{-n} e^{-\frac{6 i a}{b}} \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^n \left (\frac{\left (a+b \sin ^{-1}(c x)\right )^2}{b^2}\right )^{-n} \text{Gamma}\left (n+1,-\frac{6 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )-45 i 2^{-n} e^{-\frac{2 i a}{b}} \left (-\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,-\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )+45 i 2^{-n} e^{\frac{2 i a}{b}} \left (\frac{i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )^{-n} \text{Gamma}\left (n+1,\frac{2 i \left (a+b \sin ^{-1}(c x)\right )}{b}\right )+\frac{120 a}{b n+b}+\frac{120 \sin ^{-1}(c x)}{n+1}\right )}{384 c \sqrt{d-c^2 d x^2}} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.13, size = 0, normalized size = 0. \begin{align*} \int \left ( -{c}^{2}d{x}^{2}+d \right ) ^{{\frac{5}{2}}} \left ( a+b\arcsin \left ( cx \right ) \right ) ^{n}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (-c^{2} d x^{2} + d\right )}^{\frac{5}{2}}{\left (b \arcsin \left (c x\right ) + a\right )}^{n}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left ({\left (c^{4} d^{2} x^{4} - 2 \, c^{2} d^{2} x^{2} + d^{2}\right )} \sqrt{-c^{2} d x^{2} + d}{\left (b \arcsin \left (c x\right ) + a\right )}^{n}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (-c^{2} d x^{2} + d\right )}^{\frac{5}{2}}{\left (b \arcsin \left (c x\right ) + a\right )}^{n}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]